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-4c^2-28c-48=0
a = -4; b = -28; c = -48;
Δ = b2-4ac
Δ = -282-4·(-4)·(-48)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4}{2*-4}=\frac{24}{-8} =-3 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4}{2*-4}=\frac{32}{-8} =-4 $
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